php根据日期显示所在星座的方法

2949

这篇文章主要介绍了php根据日期显示所在星座的方法,涉及php针对日期操作与流程控制的相关技巧,具有一定参考借鉴价值,需要的朋友可以参考下.
本文实例讲述了php根据日期显示所在星座的方法。分享给大家供大家参考。具体实现方法如下：

1. <?php
   
2. function zodiac($DOB){
   
3.   $DOB = date("m-d", strtotime($DOB));
   
4.   list($month,$day) = explode("-",$DOB);
   
5.   if(($month == 3 || $month == 4) && ($day > 22 || $day < 21)){
   
6.     $zodiac = "Aries";
   
7.   }
   
8.   elseif(($month == 4 || $month == 5) && ($day > 22 || $day < 22)){
   
9.     $zodiac = "Taurus";
   
10.   }
    
11.   elseif(($month == 5 || $month == 6) && ($day > 23 || $day < 22)){
    
12.     $zodiac = "Gemini";
    
13.   }
    
14.   elseif(($month == 6 || $month == 7) && ($day > 23 || $day < 23)){
    
15.     $zodiac = "Cancer";
    
16.   }
    
17.   elseif(($month == 7 || $month == 8) && ($day > 24 || $day < 22)){
    
18.     $zodiac = "Leo";
    
19.   }
    
20.   elseif(($month == 8 || $month == 9) && ($day > 23 || $day < 24)){
    
21.     $zodiac = "Virgo";
    
22.   }
    
23.   elseif(($month == 9 || $month == 10) && ($day > 25 || $day < 24)){
    
24.     $zodiac = "Libra";
    
25.   }
    
26.   elseif(($month == 10 || $month == 11) && ($day > 25 || $day < 23)){
    
27.     $zodiac = "Scorpio";
    
28.   }
    
29.   elseif(($month == 11 || $month == 12) && ($day > 24 || $day < 23)){
    
30.     $zodiac = "Sagittarius";
    
31.   }
    
32.   elseif(($month == 12 || $month == 1) && ($day > 24 || $day < 21)){
    
33.     $zodiac = "Cpricorn";
    
34.   }
    
35.   elseif(($month == 1 || $month == 2) && ($day > 22 || $day < 20)){
    
36.     $zodiac = "Aquarius";
    
37.   }
    
38.   elseif(($month == 2 || $month == 3) && ($day > 21 || $day < 21)){
    
39.     $zodiac = "Pisces";
    
40.   }
    
41.   return $zodiac;
    
42. }
    
43. echo zodiac('1986-07-22'); //Valid strtotime date
    
44. ?>

复制代码

希望本文所述对大家的php程序设计有所帮助。